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If Na2SO4 were to dissolve in water, how many ions per molecule would be formed?

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Answer:

Three (3) => 2Na⁺ and 1SO₄²⁻

Step-by-step explanation:

Na₂SO₄ => 2Na⁺ + SO₄²⁻

Note: one can easily determine the cation-anion separation during aqueous ionization if one reads the formula left to right => place an imaginary line after the 1st metal of the molecular formula => left of line is cation and right of line anion.

Na₂SO₄ => Na₂ | SO₄ => 2Na⁺ + SO₄²⁻ (3 ions)

CaCO₃ => Ca | CO₃ => Ca₂⁺ + CO₃²⁻ (2 ions)

Ni(NO₃)₂ => Ni | (NO₃)₂ => Ni²⁺ + 2NO₃⁻ (3 ions)

Ca₃(PO₄)₂ => Ca₃ | (PO₄)₂ => 3Ca²⁺ + 2PO₄³⁻ (5 ions)

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