Answer:
Note, that the population proportion is p=0.05
So for n=200n the mean of pˆ is,
μpˆ=p=0.05
Therefore, for n=200 the standard deviation of pˆ is,
σpˆ=√(0.05)(1−0.05)/200
= √(0.05)(0.95)/200
= √0.0475/200
=√0.0002375
≈0.0154
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