Question

You have designed and constructed a solenoid to produce a magnetic field equal in magnitude to that of the Earth (5.0 10-5 T). If your solenoid has 350 turns and is 32 cm long, determine the current you must use in order to obtain a magnetic field of the desired magnitude.

Answer 1

`I = 0.03637 A`

Step-by-step explanation:

The given data in the question is

Magnetic field :
`B = 5.0 * 10^(-5) T`

Turns :
`N = 350`

Length :
`L = 32 cm = 0.32 m`

So, number of turns per unit length :

`n=(N)/(L)`

`n=(350\: turns)/(0.32 m)`

`n=1093.75 \: turns \: per \: meter`

If current is I , then magnetic field is given by

`B = \mu_(0) * n * I`

Also,

`I = (B)/(\mu_(0) * n)`

Insert the values

`I = (5.0 * 10^(-5))/(4 \pi * 10^(-7) * 1093.75) A`

`I = 0.03637 A`

The current will be
`I = 0.03637 A`