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Suppose the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour. What is the probability of observing at least two births in a given hour at the hospital?

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Answer:

0.5372

Explanation:

Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.

Let X be the no of births in the hospital per hour

X is Poisson

with mean = 1.8

the probability of observing at least two births in a given hour at the hospital

=
P(X\geq 2)\\= 1-F(1)\\= 1-0.4628\\= 0.5372

the probability of observing at least two births in a given hour at the hospital = 0.5372

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