Answer:
The area of second coil is ≅ 0.025

Step-by-step explanation:
Given :
No. of turns in the first coil

No. of turns in the second coil

Area of first coil

According to the law of electromagnetic induction,
Induced emf =
Where
magnetic flux.
Since given in question emf of both coil is same so we compare above equation.




Therefore, the area of second coil is ≅ 0.025
