Question

A sample of NO2 in a 1550 mL metal cylinder at 70.26 kPa has its temperature changed from 480oC to -237oC while its volume is simultaneously changed by a piston to 5114 mL. What is the final pressure in kPa?

Answer 1

The final pressure is 1.01325 kPa

Step-by-step explanation:

Step 1: Data given

Volume of the metal cylinder = 1550 mL = 1.550 L

Initial Pressure = 70.26 kPa = 0.69341229 atm

Initial temperature = 480 °C = 753 K

The temperature lowers to -237 °C = 36 K

The volume increases to 5114 mL = 5.114L

Step 2: Calculate the final pressure

P1*V1 / T1 = P2*V2/T2

⇒with P1 = the initial pressure = 0.69341229 atm

⇒with V1 = the initial volume = 1.550 L

⇒with T1 = the initial temperature = 753 K

⇒with P2 = the final pressure = TO BE DETERMINED

⇒with V2 = the final volume = 5.114 L

⇒with T2 = the final temperature = 36 K

P2 = 0.0100 atm = 1.01325 Kpa

The final pressure is 1.01325 kPa