Answer:
The height of the jumping hill x = 189.3 m
Explanation:
From Δ ABC
AB = x = height of the hill
∠A = 36° , ∠B = 90°
Thus ∠C = 180 - ∠A - ∠B
⇒ ∠C = 180 - 36 - 90
⇒ ∠C = 54°
From Δ ABC


x = 0.809 × 234
x = 189.3 m
This is the height of the jumping hill.