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At an amusement park, the probability that a child eats popcorn and cotton candy is 0.58. The probability that a child eats popcorn is 0.69 and the probability that a child eats cotton candy is 0.87. What is the probability (rounded to the nearest hundredth) that a child eats cotton candy given that the child has already eaten popcorn

User Rhelminen
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1 Answer

7 votes

Answer:

0.84 is the required probability.

Explanation:

We are given the following in the question:

Probability that a child eats popcorn and cotton candy = 0.58


P(p\cap c) = 0.58

Probability that a child eats popcorn = 0.69


P(p) = 0.69

Probability that a child eats cotton candy = 0.87


P(c) = 0.87

We have to evaluate the conditional probability that a child eats cotton candy given that the child has already eaten popcorn.


P(c|p)\\\\=(P(c\cap p))/(P(p))\\\\=(0.58)/(0.69)\\\\=0.84

0.84 is the probability that a child eats cotton candy given that the child has already eaten popcorn.

User Rodrigo Queiroz
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