Question

Vector 1 points along the z axis and has magnitude V1 = 80. Vector 2 lies in the xz plane, has magnitude V2 = 50, and makes a -37° angle with the x axis (points below the x axis). What is the scalar product V1·V2?

Answer 1

`\vec{V1}` .
`\vec{V2}` = 2574.08

Step-by-step explanation:

given data

magnitude V1 = 80

magnitude V2 = 50

angle a = -37°

solution

`\vec{V1}` = 80 k

`\vec{V2}` = 50 cos{37} i - 50sin{37} k

so that here
`\vec{V1}` .
`\vec{V2}` is

`\vec{V1}` .
`\vec{V2}` = 80 k . ( 50 cos{37} i - 50sin{37} k )

`\vec{V1}` .
`\vec{V2}` = 80 k . ( 38.270 i + 32.176 k )

`\vec{V1}` .
`\vec{V2}` = 2574.08