Answer:
Parameters:
![z = 1.645, \sigma = 2, n = 16](https://img.qammunity.org/2021/formulas/mathematics/college/l3dm3lekmx3bj51emr1dqj4jzorwukkmkd.png)
The 90% confidence interval for the weights, in pounds, of dogs in a city is between 27.1775 pounds and 27.8225 pounds.
Explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = (1-0.9)/(2) = 0.05](https://img.qammunity.org/2021/formulas/mathematics/college/i5j4mkziiml3cscitxoyd8jstpxa4rxxij.png)
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so
![z = 1.645](https://img.qammunity.org/2021/formulas/mathematics/college/vxcq32q4hwpu6gwjdm9nbatr48ct4fdx8n.png)
Now, find M as such
![M = z*(\sigma)/(√(n))](https://img.qammunity.org/2021/formulas/mathematics/college/cvh8tdoppqkhyobio78yaazk1nqj1870w9.png)
In which
is the standard deviation of the population and n is the size of the sample.
![M = 1.645*(2)/(√(16)) = 0.8225](https://img.qammunity.org/2021/formulas/mathematics/college/xok7hf5ptu2ud32uxc3qlmbl9b1y2lkzrh.png)
The lower end of the interval is the sample mean subtracted by M. So it is 28 - 0.8225 = 27.1775 pounds
The upper end of the interval is the sample mean added to M. So it is 28 + 0.8225 = 27.8225 pounds
The 90% confidence interval for the weights, in pounds, of dogs in a city is between 27.1775 pounds and 27.8225 pounds.