828 views
5 votes
A manufacturing plant earned $80 per a man-hour of labor when it opened. Each year, the plant earns an additional 6% per man-hour. Which expression gives the amount the plant earned per a man-hour of labor 3 years after it opened?

1 Answer

4 votes

Answer:

The expression
A(3) =80(1.06)^3 gives the amount the plant earned per a man-hour of labor 3 years after it opened.

Explanation:

Given:

Amount earned by Manufacturing Plant = $80/per man -hour labor

Percent increase in Amount earned by Manufacturing Plant each year = 6%

We need to find the expression gives the amount the plant earned per a man-hour of labor 3 years after it opened.

Solution:

Now we will use the expression;


y(t)=a(1+r)^t

Where;


y(t) ⇒ Amount after t years


a ⇒ Initial amount


r ⇒ rate of change in amount


t ⇒ Amount of time

In The given data;


y(t) =A(t)


a=80


r= 6\% =(6)/(100)=0.06

t =
3\ years

So we can say that;


A(t)= 80(1+0.06)^t=80(1.06)^t

To find the amount the plant earned per a man-hour of labor 3 years after it opened we will substitute the value of t as 3.


A(3) =80(1.06)^3

Hence The expression
A(3) =80(1.06)^3 gives the amount the plant earned per a man-hour of labor 3 years after it opened.

User Markee
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories