Question

Consider this reaction: 2Al(s) + 3 CuCl2(aq) → 2AlCl3(aq) + 3 Cu(s) If the concentration of CuCl2 drops from 1.000 M to 0.655 M in the first 30.0 s of the reaction, what is the average rate of reaction over this time interval?

Answer 1

`r=-0.0115M/s`

Step-by-step explanation:

Hello,

In this case, the rate is computed as:

`r=(C_F-C_0)/(T_F-T_0)`

As the reaction is analyzed during the first 30 seconds, the average rate will be:

`r=(0.655M-1.000M)/(30s-0s)=-0.0115M/s`

Which negative since the cupric chloride is a reagent.

Best regards.

Answer 2

rate = 0.00383 M/s

Step-by-step explanation:

The rate of reaction refers to the speed at which the products are formed from the reactants in a chemical reaction

2Al(s) + 3 CuCl2(aq) → 2AlCl3(aq) + 3 Cu(s)

The equation for reaction rate in this chemical reaction (for CuCl₂) is the following one (The value 1/3 comes from the coefficient in the chemical equation for the reaction):

`\text{rate of reaction} = - \frac{1}{\text{coefficient}} (Reactant)/(Time)`

Here, the negative sign is used to indicate the decreasing concentration of the reactant.

`rate= -(1)/(3) * (C2-C1)/(t2-t1)`

rate = - 1/3 [0.655 - 1.0 / 30]

rate = -1/3[-0.0115]

rate = 3.83 x 10-3 M/s

rate = 0.00383 M/s