Question

A piston motion moves a 25-kg hammerhead vertically down 1 m from rest to a velocity of 50 m/s in a stamping machine. What is the change in total energy of the hammerhead?

Answer 1

31.005 KJ

Step-by-step explanation:

We are given that

Mass of hammerhead=25 kg

Initial velocity,u=0

Final velocity,v=50 m/s

h=-1 m

h'=0

We have to find the change in total energy of the hammerhead.

Change in total energy=
`E_2-E_1=m(u_2-u_1)+(1)/(2)m(v^2-u^2)+mg(h-h')`

Using the formula

Change in internal energy of hammerhead=
`m(u_2-u_1)=0`

Change in total energy=
`(1)/(2)(25)(50)^2+25* 9.8(-1)`

Where
`g=9.8m/s^2`

Change in total energy=
`31005 J=(31005)/(1000)=31.005 KJ`

1 KJ=1000 J