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A helicopter is flying at an altitude of 306 meters, at an angle of depression of 38° to its landing pad. What is the distance d between the helicopter and the landing pad? Round your answer to the nearest whole number.

A helicopter is flying at an altitude of 306 meters, at an angle of depression of-example-1
User JoeR
by
4.5k points

2 Answers

8 votes

Answer:

497 m (nearest whole number)

Explanation:

As the problem has been modeled as a right triangle, we can use the sine trigonometric ratio to find the distance d.

Sine trigonometric ratio


\sf \sin(\theta)=(O)/(H)

where:


  • \theta is the angle
  • O is the side opposite the angle
  • H is the hypotenuse (the side opposite the right angle)

From inspection of the given diagram:


  • \theta = 38°
  • O = 306 m
  • H = d

Substitute the values into the formula and solve for d:


\implies \sf \sin(38^(\circ))=(306)/(H)


\implies \sf H=(306)/(\sin(38^(\circ)))


\implies \sf H=497.0263891...

Therefore, the distance d between the helicopter and the landing pad is 497 m (nearest whole number).

User AlexWerz
by
4.3k points
6 votes

Answer:

  • 497 m

Explanation:

Use tigonometry to find the value of d

  • sine = opposite side / hypotenuse
  • 306/d = sin 38°
  • d =306/sin 38°
  • d = 497 m (rounded)
User Anmol
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5.2k points