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Determine the units of the rate constant for all four reactions listed in the problem above, and enter the correct choices from the list below. Enter 4 letters in order (e.g. ABCD or CBED)a. mole L-1 sec-1

b. mole-1 L sec-1
c. mole2 L-2 sec-1
d. mole-2 L2 sec-1
e. None of the above.

User Karmel
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1 Answer

4 votes

The given question is incomplete. The complete question is :

For the net reaction:
2AB+2C\rightarrow A_2+2BC, the following slow first steps have been proposed.

A.
2C+AB\rightarrow AC+BC

B.
2AB\rightarrow A_2+2B

C.
C+AB\rightarrow BC+A

D.
AB \rightarrow A + B

Determine the units of the rate constant for all four reactions listed in the problem above, and enter the correct choices from the list below. Enter 4 letters in order (e.g. ABCD or CBED)

a.
moleL^(-1 )sec^(-1)

b.
mole^(-1)Lsec^(-1)

c.
mole^2L^(-2)sec^(-1)

d.
mole^(-2)L^2sec^(-1)

e. None of the above.

Answer: A.
2C+AB\rightarrow AC+BC :
mol^(-2)L^2s^(-1)

B.
2AB\rightarrow A_2+2B :
k=mol^(-1)Ls^(-1)

C.
C+AB\rightarrow BC+A :
k=mol^(-1)Ls^(-1)

D.
AB \rightarrow A + B:
k=s^(-1)

Step-by-step explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

1.
2C+AB\rightarrow AC+BC


Rate=k[C]^2[AB}^1


molL^(-1)s^(-1)=k[molL^(-1)]^2[molL^(-1)}^1


k=mol^(-2)L^2s^(-1)

2.
2AB\rightarrow A_2+2B


Rate=k[AB]^2


molL^(-1)s^(-1)=k[molL^(-1)]^2


k=mol^(-1)Ls^(-1)

3.
C+AB\rightarrow BC+A


Rate=k[C}^1[AB]^1


molL^(-1)s^(-1)=k[molL^(-1)]^1[molL^(-1)]^1


k=mol^(-1)Ls^(-1)

4.
AB \rightarrow A + B


Rate=k[AB]^1


molL^(-1)s^(-1)=k[molL^(-1)]^1


k=s^(-1)

User Jleleu
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