71.0k views
1 vote
The lengths, in inches, of adult corn snakes are normally distributed with a population standard deviation of 8 inches and an unknown population mean. A random sample of 25 snakes is taken and results in a sample mean of 58 inches. Identify the parameters needed to calculate a confidence interval at the 99% confidence level. Then find the confidence interval.

User Bogd
by
6.1k points

1 Answer

5 votes

Answer:

Parameters: z = 2.575

The 99% confidence interval for the lengths, in inches, of adult corn snakes are between 53.88 inches and 62.12 inches.

Explanation:

We have that to find our
\alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:


\alpha = (1-0.99)/(2) = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of
1-\alpha.

So it is z with a pvalue of
1-0.005 = 0.995, so
z = 2.575

Now, find M as such


M = z*(\sigma)/(√(n))

In which
\sigma is the standard deviation of the population and n is the size of the sample.


M = 2.575*(8)/(√(25)) = 4.12

The lower end of the interval is the sample mean subtracted by M. So it is 58 - 4.12 = 53.88 inches

The upper end of the interval is the sample mean added to M. So it is 58 + 4.12 = 62.12 inches.

The 99% confidence interval for the lengths, in inches, of adult corn snakes are between 53.88 inches and 62.12 inches.

User Karine
by
6.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.