Question

An apparatus like the one Cavendish used to find G has large lead balls that are 7.2 kg in mass and small ones that are 0.053 kg. The center of a large ball is separated by 0.063 m from the center of a small ball. Mirror m Light source M r κ The Cavendish apparatus for measuring G. As the small spheres of mass m are attracted to the large spheres of mass M, the rod between the two small spheres rotates through a small angle. Find the magnitude of the gravitational force between the masses if the value of the universal gravitational constant is 6.67259 × 10−11 N m2 /kg2 . Answer in units of N.

Answer 1

`6.41537* 10^(-9)N`

Step-by-step explanation:

Given that
`G=6.67259* 10^(-11)Nm^2/kg`, we can use Newton's Universal law of gravitation to determine the magnitude of the gravitational force as:

`F=G(m_1m_2)/(r^2)\\\\\\=G=6.67259* 10^(-11)Nm^2/kg(7.2kg* 0.053kg)/((0.063m)^2)\\\\\\=6.41537* 10^(-9)N`

Hence, the magnitude of the gravitational force between the masses is
`6.41537* 10^(-9)N`