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Find the 58th term of the following arithmetic sequence.18,25,32,39

User PKuhn
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1 Answer

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\huge\boxed{417}

Start with the formula for an arithmetic sequence, where
a_n is the
nth term of the sequence and
d is the common difference between terms.


a_n=a_1+(n-1)d

Find the difference between any two consecutive terms.


25-18=7

Substitute the known values into the formula.


a_(58)=18+(58-1)7

Subtract.


a_(58)=18+57*7

Multiply.


a_(58)=18+399

Add.


a_(58)=\boxed{417}

User Olist
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