Question

Calculate the tension in a horizontal leather string that whirls a 0.5-kg rock in a circle of radius 1.25 m when it moves at 8 m/s while being slung around a slinger's head.

Answer 1

Tension in the leather string is T = 25.6 N

Step-by-step explanation:

As we know that belt is revolving in horizontal circle

So the tension force in the belt will provide the required centripetal force

So we will have

`T = (mv^2)/(L)`

now we have

`v = 8 m/s`

L = 1.25 m

m = 0.5 kg

so we have

`T = (0.5(8^2))/(1.25)`

`T = 25.6 N`