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Suppose a population of pavement ants in Taylorsville, UT has an initial population of 3000 and 16 years later the population reaches 24000. Use an explicit exponential model to find the rate of growth and common ratio for the pavement ant population. Express the rate of growth as a percentage. Round to the nearest tenth

User Mmoya
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Final answer:

The rate of growth for the population of pavement ants is approximately 13.9%, and the common ratio is approximately 1.149, indicating a 14.9% yearly increase in the population.

Step-by-step explanation:

Finding the Exponential Growth Rate and Common Ratio

To determine the rate of growth and the common ratio for a population of pavement ants in Taylorsville, UT, we will use the formula for exponential growth:

P(t) = P0ert

Where:
P(t) is the population at time t,
P0 is the initial population,
r is the rate of growth, and
t is the time in years.

The initial population (P0) is 3000, the population at time t (P(t)) is 24000, and the time t is 16 years. Plugging in the values, we get:

24000 = 3000e16r

We can solve for r:

e16r = 24000 / 3000 = 8

16r = ln(8)

r = ln(8) / 16

After calculating, r is approximately 0.1386. To convert this to a percentage, we multiply by 100, getting 13.9%.

The common ratio is the base of the exponent e raised to the power of r. Since er is how much the population multiplies by each year, we've found it to be e0.1386, which calculates to approximately 1.149, or a 14.9% increase each year.

User Senbon
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Answer: The rate R = 1.1%

Step-by-step explanation: Please find the attached file for the solution

Suppose a population of pavement ants in Taylorsville, UT has an initial population-example-1
User Dgwyer
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