Question

In ΔEFG, the measure of ∠G=90°, the measure of ∠F=53°, and GE = 7.9 feet. Find the length of FG to the nearest tenth of a foot.

Answer 1

FG ≈ 6.0 ft

Explanation:

Using the tangent ratio in the right triangle

tan53° =
`(opposite)/(adjacent)` =
`(GE)/(FG)` =
`(7.9)/(FG)`

Multiply both sides by FG

FG × tan53° = 7.9 ( divide both sides by tan53° )

FG =
`(7.9)/(tan53)` ≈ 6.0 ft