Answer:
IF₅(g) + 2IF(g) → IF₇(g) + I₂(g)
Step-by-step explanation:
The objective is to show the balanced chemical equation.
1. Word equation (given):
- iodine pentafluoride gas + iodine fluoride gas
→ iodine heptafluoride gas + iodine gas
2. Chemical formulas for every substance:
Iodine pentafluoride gas:
- The oxidation state of F is -1 and iodine is in oxidation state +5
- IF₅
- Add the phase: IF₅(g)
Iodine fluoride gas
- The oxidation state of F is -1 and iodine is in oxidation state +1
- IF
- Add the phase: IF(g)
Iodine heptafluoride gas
- Fluorine has oxidation state -1 and iodine is in oxidation state +7
- IF₇
- Add the phase: IF₇(g)
Iodine gas:
- It is a diatomic molecule
- I₂
- Add the phase: I₂(g)
2. Write the molecular equation
- IF₅(g) + IF(g) → IF₇(g) + I₂(g)
3. Write the balanced chemical reaction
Add the coefficients to show the same number of atoms of a kind on each side of the chemical equation:
To balance F, add a 2 in front of IF(g):
- IF₅(g) + 2IF(g) → IF₇(g) + I₂(g)
Iodine is balanced.
Check:
Atom Left side Right side
I 3 3
F 7 7