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Iodine pentafluoride gas reacts with iodine fluoride gas producing iodine heptafluoride gas and iodine gas. Answer the following questions about this reaction. a. (6 pts) Fill in the missing information for the balanced chemical reaction.

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Answer:

IF₅(g) + 2IF(g) → IF₇(g) + I₂(g)

Step-by-step explanation:

The objective is to show the balanced chemical equation.

1. Word equation (given):

  • iodine pentafluoride gas + iodine fluoride gas

→ iodine heptafluoride gas + iodine gas

2. Chemical formulas for every substance:

Iodine pentafluoride gas:

  • The oxidation state of F is -1 and iodine is in oxidation state +5
  • IF₅
  • Add the phase: IF₅(g)

Iodine fluoride gas

  • The oxidation state of F is -1 and iodine is in oxidation state +1
  • IF
  • Add the phase: IF(g)

Iodine heptafluoride gas

  • Fluorine has oxidation state -1 and iodine is in oxidation state +7
  • IF₇
  • Add the phase: IF₇(g)

Iodine gas:

  • It is a diatomic molecule
  • I₂
  • Add the phase: I₂(g)

2. Write the molecular equation

  • IF₅(g) + IF(g) → IF₇(g) + I₂(g)

3. Write the balanced chemical reaction

Add the coefficients to show the same number of atoms of a kind on each side of the chemical equation:

To balance F, add a 2 in front of IF(g):

  • IF₅(g) + 2IF(g) → IF₇(g) + I₂(g)

Iodine is balanced.

Check:

Atom Left side Right side

I 3 3

F 7 7

User Gourav
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