Question

Need Help check my answer

How many grams of KNO3 will be produced if 150 grams of KI are allowed to react completely with lead nitrate
Use. 2KI + Pb(NO3)2 arrow 2 KNO3+PbI2
I got 91.4 g KNO3

Answer 1

91.27g

Step-by-step explanation:

2KI + Pb(NO3)2 —> 2KNO3 + PbI2

Molar Mass of KI = 39 + 127 = 166g/mol

Mass of KI from the balanced equation = 2 x 166 = 332g

Molar Mass of KNO3 = 39 + 14 + (16x3) = 39 + 14 + 48 = 101g/mol

Mass of KNO3 from the balanced equation = 2 x 101 = 202g

Now we can obtain the mass of KNO3 produced as follows:

From the equation:

332g of KI produced 202g of KNO3.

Therefore, 150g of KI will produce = (150x202)/332 = 91.27g of KNO3