Question

What’s the equation of the line through (-6,-5) and (-4,-4)

Answer 1

Explanation:

hello :

Hello : let A(-6,-5) B(-4,-4)

the slope is : (YB - YA)/(XB -XA)

(-4+5)/(-4+6) = 1/2

an equation is : y=ax+b a is a slope

y = (1/2)x +b

the line through point (-6,-5) : -5 = (1/2)(-6)+b

b = -2

the equation is : y =(1/2)x-2

Answer 2

y = 1/2x - 2

Explanation:

To find the equation of line

y = mx + c

Step 1: find the slope

( -6,-5) ( -4,-4)

x_1 = -6

y_1 = -5

x_2 = -4

y_2 = -4

Insert the values into

m = (y_2 - y_1) / (x_2 - x_1)

m = (-4 - (-5))/ (-4 - (-6))

m = ( -4 + 5) / ( -4 + 6)

m = 1/ 2

Step 2 : substitute slope into

y = mx + c

y = 1/2x + c

Step 3: substitute either of the points into the equation

y = 1/2x + c

Let's pick ( -6,-5)

x = -6

y = -5

y = 1/2x + c

-5 = 1/2(-6) + c

Open the bracket with 1

-5 = -6/2 + c

-5 = -3 + c

-5 +3 = c

c = -5 + 3

c = -2

Step 4: substitute c into the equation

y = 1/2x + c

y = 1/2x - 2

Therefore, the equation of the line is

y = 1/2x + c