Question

The dimensions of rectangle A are four times the dimensions of rectangle B. The area of rectangle B is 162 cm2. What is the area of rectangle A?

Answer 1

2,592 square cm.

Explanation:

It is given that the dimensions of rectangle A are four times the dimensions of rectangle B.

Let dimensions of rectangle B are l×b.

So, the dimensions of rectangle A are 4l×4b.

Area of rectangle is

`Area=length* width`

Area of rectangle B is

`A_B=l* w`

The area of rectangle B is 162 square cm.

`A_B=l* w=162`

Area of rectangle A is

`A_A=4l* 4w=16(l* w)=16(162)=2592`

Therefore, the area of rectangle A is 2,592 square cm.