Question

What is the magnetic flux going through a coil with 0.065 m2 area if the intensity of the magnetic field is 0.114 T.

Answer 1

The magnetic flux through a coil with an area of 0.065 m2 in a magnetic field of 0.114 T is 0.00741 T·m2 when the field is perpendicular to the coil.

Step-by-step explanation:

The magnetic flux through a coil can be calculated using the equation Φ = B × A × cos(θ), where Φ is the magnetic flux, B is the magnetic field intensity, A is the area of the coil, and θ is the angle between the magnetic field and the normal to the area of the coil. Since no angle is provided in the problem, we can assume that the field is perpendicular to the coil, which means cos(θ) = cos(0°) = 1. Thus, the magnetic flux Φ = B × A = 0.114 T × 0.065 m2 = 0.00741 T·m2 or Wb (webers).

Answer 2

Hi there!

`\Phi _B = \int B \cdot dA`

φ = Magnetic Flux (Wb or Tm²)
B = Magnetic field strength (T)
A = Area (m²)

This equation includes a dot product, so this can be rewritten as:

`\Phi _B = B A cos\theta`

In this instance, the field is parallel to the area, so cos(0) = 1.

Calculate the magnetic flux by plugging in the given values.

`\Phi _B = BA = 0.114 * 0.065 = \boxed{0.00741 Wb}`