Question

A 5.00 kg crate is on a 21.0 degree hill. Using X-Y axes tilted down the plane, what is the y-component of the normal force?

Answer 1

45.7

Step-by-step explanation:

just gotta round to please the sig fig rule

Answer 2

The y-component of the normal force is 45.74 N.

Step-by-step explanation:

Given that,

Mass of the crate, m = 5 kg

Angle with hill,
`\theta=21^(\circ)`

We need to find the y component of the normal force. We know that the y component of the normal force is given by :

`F_y=F\ \cos\theta\\\\F_y=mg\ \cos\theta\\\\F_y=5* 9.8\ \cos(21)\\\\F_y=45.74\ N`

So, the y-component of the normal force is 45.74 N. Hence, this is the required solution.