A 5.00 kg crate is on a 21.0 degree hill. Using X-Y axes tilted down the plane, what is the y-component of the normal force?

Question

asked Dec 9, 2021 107k views

2 Answers

MrSnrub · Answer 1 · 2021-12-13T22:53:55+0000

Answer:

The y-component of the normal force is 45.74 N.

Step-by-step explanation:

Given that,

Mass of the crate, m = 5 kg

Angle with hill,
$\theta=21^(\circ)$

We need to find the y component of the normal force. We know that the y component of the normal force is given by :

$F_y=F\ \cos\theta\\\\F_y=mg\ \cos\theta\\\\F_y=5* 9.8\ \cos(21)\\\\F_y=45.74\ N$

So, the y-component of the normal force is 45.74 N. Hence, this is the required solution.