Question

A boy twirls a 15-lb bucket of water in a vertical circle. If the radius of curvature of the path is 4 ft, determine the minimum speed the bucket must have when it is overhead at A so no water spills out.

Answer 1

11.35 m/s

Step-by-step explanation:

Given,

Weight of the bucket = 15 lb

radius of curvature, r = 4 ft

Minimum speed of the bucket = ?

Using equation of centripetal acceleration

`W=(mv^2)/(R)`

`15=((m)/(g)* v^2)/(4)`

`15=((15)/(32.2)* v^2)/(4)`

`v^2 = 128.8`

`v = 11.35\ m/s`

Speed of the bucket = 11.35 m/s