158k views
4 votes
The commute times for workers in a city are normally distributed with an unknown population mean and standard deviation. If a random sample of 20 workers is taken and results in a sample mean of 21 minutes and sample standard deviation of 6 minutes, find a 95% confidence interval estimate for the population mean using the Student's t-distribution.

User Danielius
by
8.1k points

1 Answer

6 votes

Answer:

The 95% confidence interval estimate for the population mean using the Student's t-distribution is between 10.626 minutes and 31.374 minutes.

Explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 0.99(
t_(95)). So we have T = 1.729

The margin of error is:

M = T*s = 1.729*6 = 10,374.

In which s is the standard deviation of teh sample. So

The lower end of the interval is the sample mean subtracted by M. So it is 21 - 10.374 = 10.626 minutes

The upper end of the interval is the sample mean added to M. So it is 21 + 10.374 = 31.374 minutes.

The 95% confidence interval estimate for the population mean using the Student's t-distribution is between 10.626 minutes and 31.374 minutes.

User Monifa
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.