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If k is a nonzero constant, what is the slope of the line containing the points (k,2k) and (3k,k)
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If k is a nonzero constant, what is the slope of the line containing the points (k,2k) and (3k,k)

User Shai Barack
by
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1 Answer

8 votes

Answer:

The slope is -1/2

Explanation:


m=(y_2-y_1)/(x_2-x_1)\\ \\m=(k-2k)/(3k-k)\\ \\m=(-k)/(2k)\\ \\m=-(1)/(2)

User Zaksoup
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