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Rewrite the rational expression 2x^3-7x^2+6x-9/x-3 in the form q(x)+r(x)/b(x) in nikki. Then match q(x), r(x), and b(x) to the correct expressions.​

User Geeth
by
8.0k points

2 Answers

4 votes

Answer:

whats the answer fo q(x)

Explanation:

User Bryony
by
7.0k points
4 votes

Answer:

The given expression can be written in the form
q(x)+(r(x))/(b(x)) as
(2x^2-x+3)+(0)/(x-3) where q(x)=
2x^2-x+3 , r(x)=0 and b(x)=x-3

Explanation:

Given rational expression is
(2x^3-7x^2+6x-9)/(x-3)

To rewrite the given rational expression in the given form and match their correct expressions:

Rewrite the given rational expression
(2x^3-7x^2+6x-9)/(x-3) in the form of
q(x)+(r(x))/(b(x)) where q(x) is the quotient, r(x) is the remainder and b(x) is the divisor.

Now solve the given expression by using Synthetic division, we get

Since x-3 is a factor for
2x^3-7x^2+6x-9

Therefore b(x)=x-3

3_| 2 -7 6 -9

0 6 -3 9

------------------------------------

2 -1 3 0

------------------------------------

Therefore we have quadratic equation
2x^2-x+3=0

q(x)=
2x^2-x+3

Remainder is 0

Therefore r(x)=0

Therefore we can write in the form as
(2x^2-x+3)+(0)/(x-3)

It is in the form of
q(x)+(r(x))/(b(x))

Therefore the given expression can be written in the form
q(x)+(r(x))/(b(x)) as
(2x^2-x+3)+(0)/(x-3) where q(x)=
2x^2-x+3 , r(x)=0 and b(x)=x-3

User Omi Harjani
by
7.5k points