Question

A centrifuge accelerates uniformly from rest to 15,000 rpm in220s. Through how many revolutions did it turn in this time?

Answer 1

27588

Step-by-step explanation:

Given,

Speed of the centrifuge = 15000 rpm

time, t = 220 s

Revolution = ?

1 min = 60 s

Speed of centrifuge =
`(15000)/(60)`

= 250 rps

Initial angular speed = 0 rps

`\alpha = (250-0)/(220)`

`\alpha = 1.14\ rev/s^2`

Now,

revolution

`\theta = \omega_0 t - (1)/(2)\alpha t^2`

`\theta = 0 + (1)/(2)* 1.14* 220^2`

`\theta = 27588\ rev`

Hence, the number of turns is equal to 27588.