Question

Sebuah kolom udara memiliki panjang 40cm.Jika garpu kala mempunyai frekuensi 320Hz,maka besarnya cepat rambat gelombang bunyi diudara pada saat resonasi pertama adalah....m/s.

Answer 1

Velocity of sound is 512 m/s

Step-by-step explanation:

for first resonance condition we know that

`(\lambda)/(4) = L`

`(\lambda)/(4) = 0.40`

`\lambda = 1.6 m`

now the frequency is given as

`f = 320 Hz`

now to find the velocity of sound we have

`v = \lambda f`

`v = 1.6 (320)`

`v = 512 m/s`