Question

What is the equation of a line that is parallel to -32 + 4y = 4 and passes through the point

(4, 0)?

Answer 1

-8x + y = -32

Explanation:

Where's the variable x? I will assume you meant -32x + 4y = 4.

Any line parallel to this given line has an equation of the same form but a different constant:

Substituting the coordinates (4, 0) into -32(4) + 4(0) = C, we get:

-128 + 0 + C, and so C = -128, and:

the desired equation is -32x + 4y = -128

or, after reduction, -16x + 2y = -64, or -8x + y = -32