Question

PLEASE SHOW WORK

2) If a heptagon has an area of 105 in^2, what is the measure of one side? (1 pt.)

Answer 1

5.375 in. to the nearest thousandth.

Explanation:

Area of a regular heptagon

= 7/4 * cot(pi/7) * s^2 where s is the length of one side.

105 = 7/4 * cot(pi/7) * s^2

s^2 = 105 / (7/4 cot (pi/7)

= 28.8945

s = sqrt 28.8945

= 5.375 in.