Answer:
1.69 moles of Xenon gas will occupy a volume of 37.8l in STP conditions
Step-by-step explanation:
We use the formula PV=nRT. The conditions STP are 1 atm of pressure and 273 K of temperature.
PV=nRT ----> n=PV/RT
n= 1 atm x 37, 8 L/ 0,082 l atm/K mol x 273K
n=1,688555347 mol