Answer:
0.635 grams
Step-by-step explanation:
Equation for the reaction
![Cu + 2 AgNO_3 -----> Ag^(2+) + CuNO_3](https://img.qammunity.org/2021/formulas/chemistry/middle-school/no50ezcfe9tir0iycbolk4bs0doj1dmsl0.png)
mass of Cu = 5.00 g
molar mass = 63.5 g/mol
number of moles =
![(mass)/(molar mss)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/d3i33rbfnttybtshkd6dkmq4c4mluacx0s.png)
number of moles of Cu =
![(5.00g)/(63.5g/mol)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/9eqdads7otoax5m9adwxfbx0xjuu7yfoeo.png)
number of moles of Cu = 0.0787 moles
To determine the moles of Ag formed; we have:
0.00588 moles of AgNO₃ ×
![(2 moles of Ag)/(2 moles of AgNO_3)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/7b2ky1zzf0sah7cy1vk5uw1817eoz2fffd.png)
= 0.00588 moles of Ag are produced
Molar mass of Ag = 108 g/mol
Then mass of Ag that will be produced = number of moles of Ag × molar mass of Ag
= 0.00588 moles × 108 g/mol
= 0.635 grams of Ag are produced.