Question

How much heat must your body transfer to 500.0g of water to heat it from 25.0°C to body temperature, 37.0°C?

Answer 1

Answer : The heat your body transfer must be, 25.1 kJ

Explanation :

Formula used :

`Q=m* c* \Delta T`

or,

`Q=m* c* (T_2-T_1)`

where,

Q = heat = ?

m = mass of water = 500.0 g

c = specific heat of water =
`4.18J/g^oC`

`T_1` = initial temperature =
`25.0^oC`

`T_2` = final temperature =
`37.0^oC`

Now put all the given value in the above formula, we get:

`Q=500.0g* 4.18J/g^oC* (37.0-25.0)K`

`Q=25080J=25.1kJ`

Therefore, the heat your body transfer must be, 25.1 kJ