333,000 Joules is the amount of energy (heat) in joules required to raise the temperature of 5 kg of iron from 50°C to 200°C.
Step-by-step explanation:
Data given:
mass of iron 5 Kg or 5000
initial temperature = 50 degree centigrade
final temperature = 200 degrees centigrade
change in temperature (Δ T= 200 -50 degrees centigrade)
= 150 °C
cp (specific heat capacity of iron) = 0.444j/gram C
q (heat supplied) = ?
applying the formula,
q=mcΔT
putting the values in the equation:
q = 5000 X 0.444 X150
q = 333,000 Joules of energy.
The heat required 333,000 Joules of energy is required.