Question

A sample of gas occupies a volume of 60.7 mL . As it expands, it does 145.0 J of work on its surroundings at a constant pressure of 783 Torr . What is the final volume of the gas?

Answer 1

Answer: The final volume of the gas is 1.45 L

Step-by-step explanation:

To calculate the amount of work done for an isothermal process is given by the equation:

`W=-P\Delta V=-P(V_2-V_1)`

W = amount of work done = -145.0 J = 1.431 L.atm (Conversion factor: 1 L.atm = 101.33 J)

For expansion, work done is always negative

P = pressure = 783 Torr = 1.03 atm (Conversion factor: 1 atm = 760 torr)

`V_1` = initial volume = 60.7 mL = 0.0607 L (Conversion factor: 1 L = 1000 mL)

`V_2` = final volume = ?

Putting values in above equation, we get:

`-1.431L.atm=-(1.03atm)* (V_2-0.0607)\\\\V_2=1.45L`

Hence, the final volume of the gas is 1.45 L