Question

The length and width of a rectangle or both doubled what is the ratio of the area of the larger rectangle to the area of the smaller rectangle

Answer 1

ratio of the area of the larger rectangle to the area of the smaller rectangle is 4:1 .

Explanation:

Here we have ,The length and width of a rectangle or both doubled . We need to find that the ratio of the area of the larger rectangle to the area of the smaller rectangle . Let's solve this:

Area of smaller rectangle:

Let length and breadth are x & y respectively

⇒
`Area_1 = length(width)`

⇒
`Area _1= xy`

Area of larger rectangle:

Let length and breadth are 2x & 2y( according to question sides are doubled) respectively ,

⇒
`Area_2 = length(width)`

⇒
`Area_2 = 2x(2y)`

⇒
`Area_2 = 4xy`

⇒
`Area_2 = 4Area_1`

⇒
`(Area_2)/(Area_1) = (4)/(1)`

Therefore , ratio of the area of the larger rectangle to the area of the smaller rectangle is 4:1 .