Answer:
A) 0.14
B) 0.24
C) 0.62
Explanation:
Probability of a worthy proposal being approved by the first review group = P(A) = 0.2
Probability of a worthy proposal NOT being approved by the first review group = P(A') = 1 - 0.2 = 0.8
Probability of a worthy proposal being approved by the second review group = P(B) = P(B|A) = 1 - 0.3 = 0.7 (Since the two events are described as independent events)
Probability of a worthy proposal NOT being approved by the second review group = P(B') = 0.3
A) Worthy Proposal is approved by both groups
Probability = P(A n B) = P(A) × P(B) = 0.2 × 0.7 = 0.14
B) Worthy Proposal is disapproved by both groups
Probability = P(A' n B') = P(A') × P(B') = 0.8 × 0.3 = 0.24
C) Worthy proposal is approved by one group
P(A n B') + P(A' n B) = (0.2×0.3) + (0.8×0.7) = 0.62
Hope this Helps!!!