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Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?

User Roger G
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1 Answer

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The equation of the given circle is (x+6)² + (y-2)² =10 or x² + y²+ 12x -4y +30 = 0

Explanation:

Step 1 :

Center of the given circle = (-6,2)

Radius = √10 units

We need to find the equation of this circle.

Step 2 :

Circle's equation with center at (h,k) and radius of r units is given by

(x-h)² + (y-k)² = r²

So substituting the above values

we have

(x-(-6))² + (y-2)² = (√10)²

(x+6)² + (y-2)² =10

Simplifying ,this can be written as

x² +36 + 12x + y² + 4 -4y =10

x² + y²+ 12x -4y +30 = 0

Step 3 :

Answer :

The equation of the given circle is (x+6)² + (y-2)² =10 or x² + y²+ 12x -4y +30 = 0

User Rohan Varma
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