Answer:
![2 {x}^(2) - 11x + 15](https://img.qammunity.org/2021/formulas/mathematics/middle-school/u3z0kw3fbs3mfvrhi18rl5ulbhjsho9v08.png)
Explanation:
We we're given the length of the rectangle as
![l = 2 {x} - 5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jzkh3qe1tmgxdk89brp79vy8l0lmvt7aqg.png)
and the width of the rectangle as :
![w = x - 3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kekkreakl3f1x4oca5p93fsluxf9au61s9.png)
Recall that, the area of a rectangle is
Area=l×w
We substitute the given dimensions of the rectangle into the formula to get:
![area =( 2 {x} - {5} ) *(x - 3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9nuh3vk8qkc40vx0pcu0w133amoppjpjw4.png)
We expand
![2 {x}^(2) - 6x - 5x + 15](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zlk1twtvhvgbfxuafoits4h0vxllxxbemt.png)
This simplifies to:
![2 {x}^(2) - 11x + 15](https://img.qammunity.org/2021/formulas/mathematics/middle-school/u3z0kw3fbs3mfvrhi18rl5ulbhjsho9v08.png)