Question

Dose anybody know how to solve this problem

Answer 1

check the transformation template below, hmmm so to get the graph of "y" move to the right by 1 unit, we can simply make C = -1.

`y=\stackrel{A}{1}\log_2(\stackrel{B}{1}x+\stackrel{C}{0})+\stackrel{D}{0}\qquad \qquad y=\stackrel{A}{1}\log_2(\stackrel{B}{1}x+\stackrel{C}{1})+\stackrel{D}{0} \implies y=\log_2(x-1)`

now, the x-intercept is simply where the graph touches the x-axis, and when that happens y = 0, so

`\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad a^(log_a x)=x\leftarrow \textit{let's use this rule} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{y}{0}~~ = ~~\log_2(x-1)\implies 2^0=2^(\log_2(x-1))\implies 2^0=x-1 \\\\\\ 1=x-1\implies 2=x~\hspace{10em}\stackrel{x-intercept}{(2~~,~~0)}`