Answer:
Explanation:
Given:
Carbon-14
t1/2 = 5700 years
t1 = 11400 years
t2 = 17100 years
N(t) = No(1/2)^(t/t1/2)
Where,
N(t) = amount of carbon left at time, t
No = initial amount of carbon
t = time taken
t1/2 = half life
Assume No = 1
N(11400) = 1 × (1/2)^(11400/5700)
= (1/2)^2
= 1/4
N(17100) = 1 × (1/2)^(17100/5700)
= (1/2)^3
= 1/8
From the fractions got from N(11400) and N(17100), 1/4 and 1/8 we can see a decrease in the initial amount of carbon by 1/2.
B.
t1/2 = 80000 years
N(t) = No × (1/2)^(t/80000)
Assume No = 1
N(t) = 1 × (1/2)^(t/80000)