Question

Write the equation of the line that passes through the point (-5,5) and has a slope of -8/5

A) y= -8/5 x - 3
B) y= -8/5x+3
C) 3x - 5y =0
D) 5x-3y=0

Answer 1

The equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

`y=-(8)/(5)x-3`

Explanation:

Given

• 
  `\left(x_1,\:y_1\right)=\left(-5,5\right)`

• 
  `m=(-8)/(5)`

Point-Slope Form equation is

`\left(y-y_1\right)=m\left(x-x_1\right)`

`\left(y-5\right)=(-8)/(5)\left(x-\left(-5\right)\right)`

`\mathrm{Apply\:rule}\:-\left(-a\right)=a`

`y-5=(-8)/(5)\left(x+5\right)`

`\mathrm{Apply\:the\:fraction\:rule}:\quad (-a)/(b)=-(a)/(b)`

`y-5=-(8)/(5)\left(x+5\right)`

`y-5+5=-(8)/(5)\left(x+5\right)+5`

`y=-(8)/(5)x-3`

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

`y=-(8)/(5)x-3`