Write the equation of the line that passes through the point (-5,5) and has a slope of -8/5 A) y= -8/5 x - 3 B) y= -8/5x+3 C) 3x - 5y =0 D) 5x-3y=0

Question

asked Sep 11, 2021 102k views

1 Answer

Arel · Answer 1 · 2021-09-14T23:42:28+0000

Answer:

The equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

y=-(8)/(5)x-3

Explanation:

Given

Point-Slope Form equation is

$\left(y-y_1\right)=m\left(x-x_1\right)$

$\left(y-5\right)=(-8)/(5)\left(x-\left(-5\right)\right)$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$y-5=(-8)/(5)\left(x+5\right)$

$\mathrm{Apply\:the\:fraction\:rule}:\quad (-a)/(b)=-(a)/(b)$

$y-5=-(8)/(5)\left(x+5\right)$

$y-5+5=-(8)/(5)\left(x+5\right)+5$

y=-(8)/(5)x-3

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

y=-(8)/(5)x-3