Question

PLEASE HELP ASAPPP !!!

Answer 1

Explanation:

Given the function

`f\left(x\right)=(1)/(2)\cdot 2^x`

• Putting x = -2

`(1)/(2)\cdot \:2^(-2)=(1)/(2)\cdot (1)/(4)=(1)/(8)`

so

(x, f(x)) will be (-2, 1/8)

• Putting x = -1

`(1)/(2)\cdot \:\:2^(-1)=(1)/(2)\cdot \:(1)/(2)=(1)/(4)`

so

(x, f(x)) will be (-1, 1/4)

• Putting x = 0

`(1)/(2)\cdot \:2^0=(1)/(2)`

so

(x, f(x)) will be (0, 1/2)

• Putting x = 1

`(1)/(2)\cdot \:\:2^1=2\cdot \:(1)/(2)=1`

so

(x, f(x)) will be (1, 1)

• Putting x = 2

`(1)/(2)\cdot \:\:2^2=4\cdot \:(1)/(2)=2`

so

(x, f(x)) will be (2, 2)

The graph is also attached below.