Question

Write the equation of the line that passes through the point (-5,5) and has a slope of -8/5

A) y= -8/5 x - 3
B) y= -8/5x+3
C) 3x - 5y =0
D) 5x-3y=0

Answer 1

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

`y=(-8)/(5)x-3`

Explanation:

Given the point (-5, 5)

slope = m = -8/5

Using the slope intercept form:

`y=mx+b`

Plugging point (-5, 5) and slope = m = -8/5 in the slope intercept form to find the y-intercept 'b'.

`5=(-8)/(5)\left(-5\right)+b`

`\mathrm{Switch\:sides}`

`(-8)/(5)\left(-5\right)+b=5`

`8+b=5`

`8+b-8=5-8`

`b=-3`

so the equation of the line will be:

`y=mx+b`

plugging m = -8/5 and b = -3 in slope intercept form

`y=(-8)/(5)x-3`

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

`y=(-8)/(5)x-3`