Number of beads she have is 62 .
Explanation:
Here we have , joyce has between 25 to 75 colored beads. when she makes them into groups of 9, 8 beads are left out. when she groups into groups of 8, We need to find how many beads are left . Let's solve this:
when she makes them into groups of 9, 8 beads are left out equation is
when she groups into groups of 8 , 6 beads are left out, equation is
![8y+6](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jlbe8sviijwmfaa4wbkhn8yqnzdhgzxwxo.png)
Equating both equation's we get:
⇒
![9x+8 = 8y+6](https://img.qammunity.org/2021/formulas/mathematics/middle-school/t1f9j1vmoq9a20ezsj61g7d3k4wnwlydkw.png)
⇒
![9x-8y = -2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/stvcpt9v5aeb9wfm18va25q8c1q8xbigas.png)
By hit & trial method , we put x = 6 & y=7:
⇒
![9(6)-8(7) = -2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4ya1vru02y73ep3aoy06sw416mjc1q3ejr.png)
⇒
![54-56= -2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vupcso9wds1ebthhgyje75grwnqgi1j2pr.png)
⇒
![-2= -2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/mm5jsohls12cxn32j4cdjbonoy0wkdwvgu.png)
Since , LHS = RHS x = 6 & y=7 satisfies the equation
. So putting value of x=6 in
we get:
⇒
![9x+8](https://img.qammunity.org/2021/formulas/mathematics/middle-school/nq2pc9c7pq9ggupv2wi683u9xddl1edjp1.png)
⇒
![54+8](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rab7h6w37wno99of3zt6sm15smm81uf8nx.png)
⇒
![62](https://img.qammunity.org/2021/formulas/mathematics/middle-school/xn1njmhylmgfekiyvri1vwf73es4np3jqr.png)
Therefore, Number of beads she have is 62 .